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不想输出null,覆盖父类方法
摘要: 不想输出null,覆盖父类方法
class xx extends Exception {
public xx() {
System.out.println("除数为零");
}
}
class zz {
public int aa(int x, int y) throws xx {
if (y == 0)
throw new xx();
int reslut = x / y;
return x / y;
}
}
public class test {
public static void main(String[] args) {
// TODO Auto-generated method stub
zz z = new zz();
try {
int reslut = z.aa(3, 0);
System.out.println("the reslut is" + reslut);
} catch (xx xx) {
System.out.println(xx.getMessage());
//System.exit(0);
} catch (Exception e) {
System.out.println("program is running ");
return;
} finally {
System.out.println("I love you");
}
}
}
顶
覆盖掉getMessage()方法就可以了
class xx extends Exception {
public xx() {
System.out.println("除数为零");
}
public String getMessage()
{
//System.out.println("is not null");
return "is not null";
}
}
这样就行了
解决了?
package csdn.dec;
class xx extends Exception {
public xx() {
System.out.println("除数为零");
}
}
class zz {
public int aa(int x, int y) throws xx {
int reslut = 0;
if (y == 0){
throw new xx();
}
else reslut = x / y;
return reslut;
}
}
public class Ttest {
public static void main(String[] args) {
// TODO Auto-generated method stubSystem.out.println("here?");
zz z = new zz();
try {
int reslut = z.aa(3, 0);
System.out.println("the reslut is"+ reslut );
} catch (xx xx) {
//System.out.println(xx.getMessage());
//System.exit(0);
} catch (Exception e) {
System.out.println("program is running ");
return;
} finally {
System.out.println("I love you");
}
}
}
下面是jdk的帮助
getMessage
public String getMessage()
Returns the detail message string of this throwable.
Returns:
the detail message string of this Throwable instance (which may be null).
所以你的Exception的子类成员要先覆盖父类,要不然它就返回null
是覆盖父类方法哈
使用super就可以了
例如:
========================================
class MyException extends Exception {
public MyException(String str) {
super(str);
}
};
public class Test {
public static void main(String[] args) {
try
{
throw new MyException("test by stefli");
}
catch (MyException ex)
{
System.out.println(ex.getMessage());
}
}
};
输出“test by stefli”